Question

calculate the momentum of a particle which has de broglie wavelength of 0.1 nm.??​

Answer 1

Answer:

6.625 x 10^-24 kg ms^-1

Explanation:

According to de broglie's equation.

wavelength = h/p

wavelength = h/pp = h / wavelength

Here...

Wavelength = 0.1 nm. = 0.1 x 10 ^ -9

= 10^ -10 m...

Planck's Constant(h) = 6.625 x 10 ^ -34

So...

Momentum(P )= 6.625 x 10^-34 /10^-10

= 6.625 x 10^-24 kg m/s

Answer 2

Refer to the attachment

Ans = 6.625*10^-34/10^-10

= 6.625*10^24