Question

Calculate the momentum of a particle which have de Broglie wavelength of 1A°

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Answer 1

Hey mate ..

here's the answer

P = h/ Lemda

= 6.626 * 10^-34 /1 * 10^-3

= 6.626 * 10^ -31 kg m/s

Hope it helps ❤

Answer 2

Answer:

6.6 *10^-24 kg.m/s

Step-by-step explanation:

According to the given question,

l = wavelength = 1 A°

p = momentum and h = planck's constant

And we are asked to find momentum of the particle.

We know, from modern physics that relation between wavelength and momentum of the particle is,

• l = h/p

Putting the values we get,

• 1*10^-10 = h/p

• p = h/10^-10

planck's constant = 6.6*10^ -34

• p = 6.6*10^-34/10^-10

• p = 6.6*10^-24 kg.m/s

Thus momentum of the particle is 6.6 *10^-24 kg.m/s when wavelength is 1 A°.