Question

calculate the momentum of a photon whose energy is
$1 \times {10}^{ - 12} eargs$
​

Answer 1

momentum of the photon is 3.3 × 10^-26 Kgm/s

we have to find momentum of a photon whose energy is 10^-12 ergs.

we know, 1J = 10^5 ergs

so, energy of photon, E = 10^-17 J

using E = hc/λ = 10^-17

⇒h/λ = 10^-17/c

from De - broglie wavelength equation, λ = h/p

so, p = h/λ

hence, momentum = h/λ = 10^-17/c

= 10^-17/(3 × 10^8)

= 1/3 ×10^-25

= 0.33 × 10^-25

= 3.3 × 10^-26 Kgm/s

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Answer 2

$\huge\bold\purple{Answer:-}$

we have to find momentum of a photon whose energy is 10^-12 ergs.

we know, 1J = 10^5 ergs

so, energy of photon, E = 10^-17 J

using E = hc/λ = 10^-17

⇒h/λ = 10^-17/c

from De - broglie wavelength equation, λ = h/p

so, p = h/λ

hence, momentum = h/λ = 10^-17/c

= 10^-17/(3 × 10^8)

= 1/3 ×10^-25

= 0.33 × 10^-25

= 3.3 × 10^-26 Kgm/s