Question

calculate the momentum of an electron and associated wavelength when kinetic energy is 150ev​

Answer 1

solution

At equilibrium, Kinetic energy is accelerating potential.

2

mv

2

=eV

v=4.44×10

6

m/s

P=mv

⇒9.1×10

−31

×4.44×10

6

=4.04×10

−24

where m is the mass of the electron.

(b) De Broglie wavelength is given by

λ=

V

12.27×10

−10

⇒

56

12.27×10

−10

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=0.164 nm

Answer 2

Answer:

At equberillium kinetic energy is accelerating potential