Question

Calculate the momentum of electrons if their wavelength is 2 Ampere. Given h=6.626multily 10 raise to power minus 34 joule second And mass of earth equal to 10 raise to power 9.1 multiply 10 raise to power minus 31 kg.

Answer 1

Answer:

Given:

Mass of an Electron = 9.1 × 10–31 kg

Kinetic Energy, K.E. = 3.0 × 10–25 J

1/2 mv2 = kinetic Energy

Where

m = mass of electron

v = velocity of electron

v2 = [2× 3.0 × 10–25] / [9.1× 10-31]

= [6.0 × 10–25] / [9.1× 10-31]

v2 = 659.3406 × 103

Therefore v = √ [659.3406 × 103]

v = 811.99 m/s

According to the de Broglie’s Equation:

λ = h/mv

Where,

λ = wavelength of moving particle

m = mass of electron

v= velocity of particle

h= Planck’s constant [6.62× 10-34]

λ = {[6.62× 10-34] / [9.1× 10-31] × [811.99]}

= {[6.62× 10-34] / [7.389 × 10-28]

= 8.959× 10-7 m

Therefore, the wavelength is 8.96× 10-7 m