Question

calculate the momentum of inertia of thin uniform rod of mass 100 gram and length 15 CM about an axis perpendicular to its length passing through 1) it's centre 2)one end
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Answer 1

Answer:

1) 0.002

2) 0.008

Explanation:

100 g = 0.1 kg 50 cm = 0.5 m

Formula : 1. its centre : ml^2 / 12 = 0.1*(0.5)^2 / 12 = 0.00208333333 2. its end : ml^2 /3 = 0.1 *(0.5)^2 /3 = 0.00833333333

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