Question

calculate the momentum of moving particle with de brogle wave length is 2Ao where h =6.625*10^-34​

Answer 1

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Actually Welcome to the Concept of the Debroglie's wavlength that is given as

Lambda = h / p

here,

h = planck's constant and, p= momentum of the body

so after solving we get as

p = h/lambda

p= 6.626 * 10^-34 joules / 2 * 10^-10

so we get as

p = 3.313 * 10-24 kg m/s

Answer 2

Answer:

Wavelength is an important parameter of waves and is the distance between two like points on the wave. The wavelength is calculated from the wave speed and frequency by λ = wave speed/frequency, or λ = v / f. A peak is the highest point of a wave, while the valley is the lowest point of a wave.

Explanation:

Lambda = h / p

here,

h = planck's constant and, p= momentum of the body

so after solving we get as

p = h/lambda

p= 6.626 * 10^-34 joules / 2 * 10^-10

so we get as

p = 3.313 * 10-24 kg m/s