calculate the monthly bill for a heater of resistance 40ohm,which is used on 220V mains,such that it's daily use is for 5 hours .the cost of electric energy is RS.3.60 per kwh
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The Cost of the electricity will be Rs 653.4
According to the question, we are given,
V=220V
R=40.5Ω
Power of heater = P = V²/R
=(220)²/40
=48400/40
Power = 1210w
The total energy consumed by heater in 30 days
⇒1210w×5×30
⇒1210w×150wh
=181500Wh, which equals to
181.5kwh (as 1KW=1000w)
Cost of energy for 30 days
=181.5kwh×₹3.6kwh
=₹653.4
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