Physics, asked by shama36, 11 months ago

calculate the monthly bill for a heater of resistance 40ohm,which is used on 220V mains,such that it's daily use is for 5 hours .the cost of electric energy is RS.3.60 per kwh​

Answers

Answered by khushi0037
27

Hey mate!

Here is your answer

Hope it helps

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Answered by rakeshmohan73
4

The Cost of the electricity will be Rs 653.4

According to the question, we are given,

V=220V

R=40.5Ω

Power of heater = P = V²/R

=(220)²/40

=48400/40

Power = 1210w

The total energy consumed by heater in 30 days

⇒1210w×5×30

⇒1210w×150wh

=181500Wh, which equals to

181.5kwh (as 1KW=1000w)

Cost of energy for 30 days

=181.5kwh×₹3.6kwh

=₹653.4

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