Calculate the monthly bill for a heater of resistance 50Ω, which uses 200V mains, such
that its daily use in 4 hr. The energy costs Rs.2.50 per kWh.
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Answer:
power consumption = V^2/R
= 200×200/50
= 800watt
energy consumed = P×t
= 800×4×30
=96000wh = 96 kwh
total bill = 96 × 2.5
=240 rupees
Answered by
0
Answer:
power consumption = V²/R =(200*200) / 50
= 800Watt
Energy consumed = P*T = 800*4*30 = 96000wh
= 96kwh
TOTAL BILL = 96*2.5 = 240 RUPEES
Explanation:
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