Question

calculate the monthly bill for a heater of resistance 50ohm which is used on 200 volt main supply and used for 4 hours everyday.the energy cost is 2.50kwh​

Answer 1

Answer:

8 rupees

Explanation:

Given:

• Resistance of the heater = 50 ohms

• Voltage or potential difference across the heater = 200 volts

• Time the heater was on for each day = 4 hours

• Cost of each kwh= 2.5 rupees

To find :

• Monthly bill

Power = V²/r

Power = 200×200/50

Power = 40,000/50

Power = 800 Watts

Daily consumption = 800×4 = 3200 Watt hours = 3.2 Kilo watt hours

Rate per unit = rs. 2.5

Monthly bill = 2.5×3.2

Monthly bill = 8 rupees

The monthly bill of the heater is equal to 8 rupees

Answer 2

Answer:

Given and Find:

• Calculate the monthly bill for a heater of resistance 50 ohm which is used on 200 volt main supply and used for 4 hours everyday. the energy cost is 2.50 kwh.

Using formula:

☆ ${\sf{\underline{\boxed{\orange{\sf{Power = \dfrac{Voltage^2}{Resistance} }}}}}}$

Know terms:

1. Power = (P)
2. Voltage = (V)
3. Resistance = (R)
4. Watt = (W)
5. Kilo watt = (Kw)
6. Monthly bill = (a)

Calculations:

⇒ $\bold{P= \dfrac{200 \times 200}{50}}$

⇒ $\bold{P = \dfrac{40000}{50}}$

⇒ ${\sf{\underline{\boxed{\red{\sf{P = 800 \: W }}}}}}$

⇒ $\bold{Daily \: usage = 800 \times 4}$

• 3200 W hrs = (3.2 KW hrs)

⇒ $\bold{Per \: 1 \: unit = 2.5}$

⇒ $\bold{a = 2.5 \times 3.2}$

⇒ ${\sf{\underline{\boxed{\red{\sf{ a = 8 \: rupees}}}}}}$

Therefore, 8 rupees is the monthly bill of the heater.