Question

calculate the monthly bill for heater of resistance 40 ohm which is used on 220V mains such that its daily use is for 5 hrs. the cost of electric energy is Rs.3.60 per kwh.

Answer 1

Answer:

P=V^2 = (220)^2 =1210W

R 40

Energy=P×T= 1210×5=6050Wh

Cost=6050×3.60= Rs.21780

or if E=6.05 kWh

then, cost= 6.05×3.60= Rs.21.78