Question

calculate the monthly electricity bill for a household having used the following electrical loads on an average :-
1) 40W tube lights ,4 no's ,6hours per day
2)80 W ceiling fans ,3no's ,12hours per day
3)250 W electrical iron ,1 no,6 hours per day
supply voltage is 230 V ,single phase ,50 Hz . Each unit of electricity charge is Rs. 6.50 only.

Answer 1

Electrical energy consumed;

=$\sf{\dfrac{ No \: of \: appliance\: × Power × time}{1000}}$

From question we have;

• Power = 40w + 80w + 250w = 370w
• Time = 6 + 12 + 6 = 24
• No of appliance = 4 + 3 + 1 = 8

Put all the values in the above formula:-

=$\sf{\dfrac{8× 370 × 24}{1000}}$

= $\sf{\dfrac{2960× 24}{1000}}$

= $\sf{\dfrac{71,040}{1000}}$

= $\sf{71.04}$

Now, cost of electricity consumed;

= 6.50 × 71.04

= Rs 461.76