Question

calculate the mortality of a solution of NaCl in water if it is given that are 54 grams of NaCl is dissolved in 10 moles of water ??

Answer 1

Answer :-

Given, No of moles of water = 10 moles

We know at ideal conditions i.e. at STP = 1 mole of a liquid = 22.4L

So, 10 moles = 10 * 22.4 = 224 L

Now, molar mass of NaCl = 23 + 35.5 = 58.5g

No of moles of Nacl = Given mass / Molar mass

= 54/ 58.5 = 0.92 moles

Therefore, Molarity = No. of moles of solute / Volume of solution in litres

Molarity = 0.92/ 224 = 0.004 M answer

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