Question

Calculate the motional emf induced
along a 20.0 km long conductor movin
at an orbital speed of 7.80 km/s
perpendicular to the Earth's 5.00x10-5T
magnetic field.​

Answer 1

Answer:

To find the magnitude of emf induced along the moving rod, we use Faraday’s law of induction without the sign:

emf

=

N

Δ

Φ

Δ

t

Explanation:

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Answer 2

Answer:

Strategy

This is a straightforward application of the expression for motional emf — emf = Bℓv.

Explanation:

Solution

Entering the given values into emf = Blv gives

emf = Blv

=(5.00 x 10-5T) (2.0 x 101 m (7.80 × 10³ m/s)

= 7.80 × 10³ V