Question

Calculate the mss of nh4cl to prepare a 0.5l of 1000 mg n/l

Answer 1

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Answer 2

a)   0.1 M NaCl =   0.1 mol     x                 x = 0.025 moles of NaCl present
                               1000 mL     250 mL

MNaCl = 58.44 g/mol

m = n • M = 0.025 mol • 1.46 g

6H12O6 =   0.44 mol     x                 x = 0.044 moles of glucose present
                                        1000 mL        100 mL

Mglucose = 180.18 g/mol

m = n • M = 0.044 mol • 

   0.50 mol     x                 x = 0.25 moles of H2O2 present
                                 1000 mL        500 mL

MH2 = 34.02 g/mol

m = n • M = 0.25 mol • 34.02 g/mol =8.51 g