Question

calculate the narmality of a solution prepared by dissolving 5.3 of Na2CO3 in 250ml of solution​

Answer 1

Answer:

Molecular mass of Na

2

CO

3

=106 gmol

−1

∴ Number of moles =

106

53

=0.05mol

As 0.05 mol are dissolved in 250mL;

Number of moles dissolved in 1000mL (1L) or molarity of th solution

=

0.05*1000/250 = 0.2 M