Calculate the net force acting on the block.
A=5kgwt , B=10N
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Force, F=10N
Mass, m=5Kg
Force,
F=ma
a=2m/s
2
Work done, W=F.ds
In first second, displacement,
s=
2
1
at
2
s=
2
1
×2×1
s=1m
So, work done,W=10×1=10J
In second second, s=
2
1
×2×4=4m
So, the displacement is , 4−1=3m
Hence, work done in 2 second is,
W=10×3
W=30J
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