Calculate the net force on the given box - 6 N 6 N 3 N. Please
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Answer:
Let F be force exerted on 2kg block by 1kg block,
So Free body diagram:
For 2kg block,
6−F=2×a−−−(1)
Explanation:
where a is the acceleration of two blocks
For 1kg block
F−3=1×a⇒a=F−3
Put this value in equation (1)
6−F=2×(F−3)⇒3F=12⇒F=4N
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