Question

Calculate the net torque on the system about point o as shown in figjre if f1=11n f2=9n

Answer 1

where is the figure
send the figure first

Answer 2

Answer: The net torque is $90(3+\sqrt { 3 } ) N$

Image

Where $r_1= b=20$ and $\theta \quad =\quad 90^{o}$

          $\tau_1\quad =\quad F_1\times r1\\\tau_1\quad =\quad F_1b\sin { \theta }\\ \tau_1\quad =\quad 11(20)(1)\\\tau_1\quad =\quad 220N$

where $r_2=20$ and \theta \quad =\quad 60°

           $\tau_2\quad =\quad F_2\times r_2\\\tau _2\quad =\quad F_2b\sin {\theta }\\ =9(\frac { 20 }{ 10 } )\frac { \sqrt { 3 } }{ 2 }\\ \tau _2\quad =\quad 90N$

where $r_3 =a=10cm$

            $\tau _3\quad =\quad F3\times r3\tau _3\quad =\quad 10(10)\sin { \theta }\\ \tau _3\quad =\quad 100\sin { 30^{o} }\\ \tau _3\quad =\quad 100(\frac { 1 }{ 2 } )\quad =\quad 50N\\\tau _{net}\quad =\quad \tau _1+\tau _2+\tau _3\\=\quad 220+50+90\sqrt { 3 } =\quad 90(3+\sqrt { 3 } )N$

Therefore, the net torque is $90(3+\sqrt { 3 } ) N$