Calculate the net torque on the system about the point o as shown in figure if F= 11 N, F2 = 9 N,F3 = 10 N, a = 10 cm and b= 20 cm. (All the forces along the tangent.)
Attachments:
Answers
Answered by
86
Hola User__________________
Here is Your Answer...!!
__________________________
⭐Actually welcome to the concept of the MOMENT OF FORCE (TORQUE )
⭐Basically we know that ...
⭐T (tau) = F × r
⭐since it's a cross product ...
⭐we get the torque as
⭐T = F.rsin⊙
⭐Now here applying the torque equation at the point of application of force we get
__________________________
Hope it helps u.....☺
Here is Your Answer...!!
__________________________
⭐Actually welcome to the concept of the MOMENT OF FORCE (TORQUE )
⭐Basically we know that ...
⭐T (tau) = F × r
⭐since it's a cross product ...
⭐we get the torque as
⭐T = F.rsin⊙
⭐Now here applying the torque equation at the point of application of force we get
__________________________
Hope it helps u.....☺
Attachments:
Anonymous:
Nice answer ^_^
Answered by
3
Answer:
Net torque on the system about the point O is 3 N-m clockwise.
Explanation:
Given,
F= 11 N, F2 = 9 N,F3 = 10 N, a = 10 cm or 0.1 m and b= 20 cm or 0.1m.
To find: The net torque on the system about the point O.
Solution:
All the forces are acting along tangent. So we need not to check angles.
Anticlockwise is taken postive and clockwise is taken negative.
Net torque will summation of all forces with their sign.
τ = - F₁ . b - F₂ .b + F₃.a
τ = - (F₁ + F₂) b + F₃a
τ = - (11 + 9) * 0.2 + 10 × 0.1
τ = -4 + 1 Nm
or, τ = - 3 Nm
or, τ = 3 N - m ( clockwise)
Therefore, Net torque on the system about the point O is 3 N-m clockwise.
Similar questions