Question

calculate the new molarity when 100cm^3 of water is added to 100cm^3 of 0.5 M HCL​

Answer 1

Answer:

∵N  

1

​  

V  

1

​  

=N  

2

​  

V  

2

​  

 

Given,

N  

1

​  

=0.5 N,  

N  

2

​  

=0.1 N,

V  

1

​  

=100 cm  

3

,  

V  

2

​  

=?

∴0.5×100=0.1×V  

2

​  

 

V  

2

​  

=500 cm  

3

 (Total final volume)

∴ Volume to be added

=500−100=400 cm  

3

.

Explanation: