Question

calculate the nhmber of molecules of water present in 36g of water.​

Answer 1

Answer:

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Explanation:

Answer. It is equal to Avogadro's number (NA), namely 6.022 x1023. If we have one mole of water, then we know that it will have a mass of 2 grams (for 2 moles of H atoms) + 16 grams (for one mole O atom) = 18 grams. Since we only have 0.001 grams, that means that we have NA * (0.001/18) = 3.35*1019 molecules of water!

Answer 2

Explanation:

Molar mass of H2O = 18 g

mass of H2O = 18 gNo. of molecules present in 1 mole of H2O = 6.022×1023

mass of H2O = 18 gNo. of molecules present in 1 mole of H2O = 6.022×1023No. of moles of H2O = 1836=2

mass of H2O = 18 gNo. of molecules present in 1 mole of H2O = 6.022×1023No. of moles of H2O = 1836=2So, the no. of molecules of H2O present in 2 moles of H2O = 2×6.022×1023=1.2044×1024