Calculate the no molecule in a drop of water weighing 0.048
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hey..........
=
18 g of H2O has 6.022 × 10^23 molecules
= 0.048 g of H2O will have
= ( 6.022 × 10^23 × 0.048 ) / 18
= 1.606 × 10^21 molecules..
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i hope this helps u.
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=
18 g of H2O has 6.022 × 10^23 molecules
= 0.048 g of H2O will have
= ( 6.022 × 10^23 × 0.048 ) / 18
= 1.606 × 10^21 molecules..
.
.
i hope this helps u.
.
mark me brainliest plz plz plz plz
anjali962:
mark it as brainliest i request u
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