Question

Calculate the no No3- ions present in 2.1g of HNo3​

Answer 1

Answer:

2.01* 10^22 ions

Explanation:

Molecular mass of HNO3 = 63g

1 mol of HNO3 dissociates into 1 Mol of NO3 - ions

In other words there are Avogadro numbe(N) of NO3 - ions in 63g of HNO3

Therefore in 2.1 g there are (2.1/63)* (6.02*10^23) ions

=2.01* 10^22 NO3-

Hope this helps.