calculate the no of aluminium ion in 0.056 of alumina
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If you rearrange that expression,
mol = mass/Molar mass
n = m/Mr
Now, There is a formula for finding out the number of ions in a compound. It is,
number of particles = mol * 6.02×1023
Since 1 mol of any substance contains that many number of that particle.
Now, the formula of aluminium oxide is Al2O3. This means, for every 1 mol of Al2O3, there are 2 mol of Aluminium ions. Let's plug the values in, then!
n = M/Mr
n = 0.051/102.0
n = 5.0×10−4 mol
Now,
number of particles = mol * 6.02×1023
number of particles = 5.00×10−4 * 2 * 6.02×1023
= 6.02×1020
So, there are 6.02×1020 aluminium ions in the given
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