Math, asked by zainabzainab60366, 2 months ago

calculate the no of aluminum ions present in 0.051 g of aluminum
please explain

Answers

Answered by sonybunny9391

1

Answer:

6.022×10 to the power of 20

Al+3 ions

Step-by-step explanation:

Molar mass of Al2O3=2×27+3×16= 102gm

0.051 gm of Al2O3

Contains=2×6.022×10 to the power of 23/102

= 6.022×10 to the power of 20 (or) Al +3 ions

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