Question

Calculate the no. Of atom of each element present in 53g Na2CO3?

Answer 1

no. of moles = 53/106

= 0.5

no. of atom of na = 0.5*2*Na

(Na= 6.022*10^23)

no.of atom of c= 0.5*Na

no.of atom of o = 0.5*3*Na