Question

calculate the no. of atom present in 11gm of co2

Answer 1

HOLA friend!!
Rajdeep here.....

How many atoms are present in 11gm of Carbon dioxide?

Hope you know the Avogadro's number....
After rounding it off,
Avogadro's number is:
$6\times10^{23}$

Atomic mass of C = 12,
Atomic mass of O = 16

Molecular mass of CO₂ = 12 + (2x16) = 12 + 32 = 44

Now,
We know
..
..
Number of atoms present in 44g CO₂ is 6 x 10²³

Hence, number of atoms present in 1g CO₂ is:
$\frac{6\times10^{23}}{44}$

Hence, number of atoms in 11g of CO₂ is:

[tex] \frac{6\times10^{23}}{44} \times 11 \\= \frac{6\times10^{23}}{4} \\= 1.5 \times 10^{23}[/tex]

Hence, there are 1.5 x 10²³ atoms in 11g of CO₂

Thanks!!

Answer 2

Answer:

No. of molecules present in 11 gms of CO₂ is 1.5058×10²³ according to the below-given calculations.

Explanation:

No. of moles of CO₂ is (Given mass of CO₂)/(Molecular mass of CO₂)

=  $\frac{11 gms}{44 gms}$

= 0.25

No. of molecules is (No. of moles ) ×(Avogadro number(6.023×10²³))

No. of molecules in 11gms of CO₂  = 0.25 × (6.023×10²³) [According to the above equation]

= 1.5058×10²³

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