Question

Calculate the no of atoms and molecules in 4.8 oxygen 4.4 carbon-dioxide and 3.40 ammonia

Answer 1

Answer:

no of molecules= n x avagadro no

Explanation:=4.8/16x6x10^23=3x10^22 molecules

no of atoms = no of moleculesxatomicity=3x10^22x2=6x10^22 atoms            for CO2 no of mol=nx a.no=4.4/44x6x10^23=6x10^22 molecules . no of atoms = noof molx atomicity=6x10^22x3=18x10^22 atoms . then no of mol of NH3=nxA.no=3.4/17x6x10^23=12x10^22 molecules.no of atoms =no of mol x atomicity=12x10^22x4=48x10^22 atoms....hope u like this ........