Calculate the no of atoms and the no of molecules in 11.2lt of oxygen at nth
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What is the number of atoms and number of molecules in 11.2 litres of oxygen gas at STP?
Note: 1 molecule of oxygen contains 2 oxygen atoms (O + O = O₂).
1 mole of oxygen gas contains 22.4 litres of Oxygen at STP.
Avogadro's constant = 6.023 x 10²³
[Here, for simplicity in calculations, you can take it as 6 x 10²³].
Hence, from the above data,
In 22.4 litres of oxygen, there are 6 x 10²³ molecules.
∴ In 11.2 litres of oxygen, there are:
molecules
On calculation, you get the value = 3 x 10²³ molecules.
Now, 1 molecule of Oxygen contains 2 atoms,
So, 3 x 10²³ molecules will contain 2 x 3 x 10²³ atoms
= 6 x 10²³ atoms
HOPE MY ANSWER IS SATISFACTORY.....
Thanks!
What is the number of atoms and number of molecules in 11.2 litres of oxygen gas at STP?
Note: 1 molecule of oxygen contains 2 oxygen atoms (O + O = O₂).
1 mole of oxygen gas contains 22.4 litres of Oxygen at STP.
Avogadro's constant = 6.023 x 10²³
[Here, for simplicity in calculations, you can take it as 6 x 10²³].
Hence, from the above data,
In 22.4 litres of oxygen, there are 6 x 10²³ molecules.
∴ In 11.2 litres of oxygen, there are:
molecules
On calculation, you get the value = 3 x 10²³ molecules.
Now, 1 molecule of Oxygen contains 2 atoms,
So, 3 x 10²³ molecules will contain 2 x 3 x 10²³ atoms
= 6 x 10²³ atoms
HOPE MY ANSWER IS SATISFACTORY.....
Thanks!
Answered by
0
1 molecule of oxygen contains 2 oxygen atoms (O + O = O₂).
1 mole of oxygen gas contains 22.4 litres of Oxygen at STP.
Avogadro's constant = 6.023 x 10²³
In 22.4 litres of oxygen, there are 6 x 10²³ molecules.
In 11.2 litres of oxygen, there are
\frac{6 \times 10^{23} \times 11.2 }{22.4}22.46×1023×11.2
molecules
value = 3 x 10²³ molecules.
1 mole of oxygen gas contains 22.4 litres of Oxygen at STP.
Avogadro's constant = 6.023 x 10²³
In 22.4 litres of oxygen, there are 6 x 10²³ molecules.
In 11.2 litres of oxygen, there are
\frac{6 \times 10^{23} \times 11.2 }{22.4}22.46×1023×11.2
molecules
value = 3 x 10²³ molecules.
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