Question

calculate the no of atoms and volume of 1g of Helium gas at N.T.P

Answer 1

howdy , your answer is ---

we know that atomic number of helium is 2 .
so , atomic mass of helium is 4amu .
now, 1 mole of helium = 4 gram ..(1)

also ,1 mole of helium = 6.002×10^23 atom. ....(2)

from (1) and (2)

6.002×10^23 = 4 gram
or , 1 gram = 6.002×10^23/4
=> 1 gram = 1.5 × 10^23 particle

now , at NTP

1 mole of helium = 22.4 L
so, 4 gram = 22.4 L
=> 1 gram = 22.4/4 L

=> 1 gram = 5.6 L

hence , 1 gram of helium gas = 1.5×10^23 particles and
1 gram of helium gas = 5.6 L Volume


hope it help you ★

Answer 2

Answer:

Mass of he =4

Mass given=1g

Now,

We know that

Explanation:mass given/molar mass

=1/4

We know that

1 mole=6.022×10^23atom

So,1/4mole=1/4×6.022×10^23atom

=1.50×10^23 atom