Calculate the no. of atoms in 12.2litre of the monoatomic gas at NTP
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Answer:
3.19×10^23
Explanation:
22.7 L of monoatomic gas at NTP = 1mol of monoatomic gas
12.2L of monoatomic gas at NTP =( 1/22.7L)×(12.2L)
= 0.53 mol
=3.19×10^23 molecules
Answered by
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Explanation:
(i) 22.7 L of monoatomic gas at NTP = 1mol of monoatomic gas
12.2L of monoatomic gas at NTP =( 1/22.7L)×(12.2L)
= 0.53 mol
=3.19×10^23 molecules
(ii) 22.7 L of diatomic gas at NTP = 1mol
12.2 L of diatomic gas at NTP = 0.53 mol
= 3.19×10^23×2 = 6.38×10^23 atoms of diatomic gas
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