Calculate the no of atoms in 2.5 moles of mg
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10
No. of mole=2.5
Molar mass of Mg=24 g
Mass=Molar mass× No. of mole
= 24×2.5
= 60 g
Now,
No. of atoms=Mass÷Molar mass×Avogadro's no.
=60÷24×6.022×10^23
=1.5055×10^23
Molar mass of Mg=24 g
Mass=Molar mass× No. of mole
= 24×2.5
= 60 g
Now,
No. of atoms=Mass÷Molar mass×Avogadro's no.
=60÷24×6.022×10^23
=1.5055×10^23
Answered by
2
Answer:
No. of mole=2.5
Molar mass of Mg=24 g
Mass=Molar mass× No. of mole
= 24×2.5
= 60 g
Now,
No. of atoms=Mass÷Molar mass×Avogadro's no.
=60÷24×6.022×10^23
=1.5055×10^23
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