Question

calculate the no. of atoms in 23 gm of sodium?

Answer 1

$\huge\mathfrak{Solution :}$

Given Mass of Sodium (Na) = 23 g

Molar Mass of Sodium (Na) = 23 g

$\textbf{No. of moles = Given mass / Molar}$
$\textbf{mass}$

•°•

No. of moles of Sodium = 23 / 23 = 1 mole

As we know,

1 mole of any substance contains =>

$6.022 \times {10}^{23}$ Atoms / molecules / ions.

$\textbf{Hence,}$

23 g of Sodium contains $6.022 \times {10}^{23}$
Atoms.

$\huge\mathbb{Hope \ this \ helps.}$

Answer 2

First find the molar mass.
Molar mass of sodium (Na) is 23g/m.
For converting grams to mole = Mass (g) * 1 mol/ molar mass. The grams are cancelled out and the remaining we will get no of moles. There are 6.02*10^23 atoms in each mole (Avagadro no.)
That is x moles * avagadro no.
x * 6.02 * 10^23/1 mole
According to that, in 23 grams of sodium we have 6.02*10^23 atoms of Na.