calculate the No of atoms in 39.4g gold. Molar mass
of gold is 197g /mol..
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Answer:
1.2×1023.
Explanation:
As molar mass of gold is 197gmole−1 , and number of atoms = Avogadro's number =6.023×1023
∴ no of atoms in 39.4g gold = 6.023×1023×39.4197=1.2×1023.
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