Question

Calculate the no. of atoms of C,H&O in 0.18 g of C6 H12O6​

Answer 1

Explanation:

no. of atoms of C

=no.of molecules*total no. of C atoms

=moles*NA*total no. of C atoms

=0.18/180*6.022*10²³*6

=0.001*6.022*10²³*6

=0.006*6.022*10²³

=0.036*10²³

=3.6*10²¹

no. of atoms of H

=no.of molecules*total no. of atoms of H

=moles*NA*total no. of atoms of H

=0.18/180*6.022*10²³*12

=0.001*6.022*10²³*12

=0.012*6.022*10²³

=0.072*10²³

=7.2*10²¹

no. of atoms of O

=no.of molecules*total no. of atoms of O

=moles*NA*total no. of atoms of O

=0.18/180*6.922*10²³*6

=0.001*6.022*10²³*6

=0.006*6.022*10²³

=0.036*10²³

=3.6*10²¹

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