Question

Calculate the No. of Atoms of
Carbon, Hydrogen & Oxygen in 90grams of Glucose. ​

Answer 1

Answer:

Your answer MATE

Explanation:

Molecular formula =C6H12O6

Molar mass =6×12+12×1+16×6=180gmol−1

Moles in 18g of sample=18018=0.1mole

So,moles of carbon present in sample=0.1×6=0.6

Moles of hydrogen=0.1×12=1.2

Moles of oxygen=6×0.1=0.6

No. of atoms present in carbon=0.6×6.022×1023=3.6×1023

No. of atoms present in hydrogen=1.2×6.022×1023=7.2×1023

No. of atoms present in oxygen=0.6×6.022×1023=3.6×1023

HOPE IT HELPS YOU MATE

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Answer 2

Answer:

use formula 6.22 into 10to di power minus 18 ..........