Question

Calculate the no. of atoms of each element present in 4.9 gm of HH2SO4

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Answer 1

Answer:

2.1×10

23

atoms

Explanation:

No. of atoms in 4.9g of H

2

SO

4

1moleofH

2

SO

4

⟶6.022×10

23

atoms

No.ofmole=

98

4.9

=

98×10

49

=

20

1

=0.05

0.05moleofH

2

SO

4

⟶0.05×6.022×10

23

atoms

⟶0.3011×10

23

molecules

No. of atoms in 4.9g of H

2

SO

4

=8×3.011×10

22

atoms=2.1×10

23

atoms

Answer 2

Answer:

please refer to the attachment