Calculate the no of atoms of each type in 122.5 g of kclo3
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Answer:
K = 6.022×10^23
Cl=6.022×10^23
O =18.099×10^23
Explanation:
moles of KClO3 present = 1 mole
1 mole of KClO3 contains 1 mole of K ,1 mole of Cl and 3 moles of O
so we can get the no. of each element
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