Question

Calculate the no of atoms of hydrogen in 5.6 litre of ammonia

Answer 1

22.4L of NH3 ---- 1 Mole

5.6 L of NH3 = ? mole

therefore, 5.6L of NH3 = 5.6/22.4 moles

= 0.25 moles

Now, 1 Mole of NH3 contains 6.022 x 1023 molecules

hence, 0.25 moles of NH3 contain= 6.022 x 1023 x 0.25

= 1.505 x 1023 molecules

1 Molecule of NH3 = 1+3

= 4 atoms

therefore, 1.505 x 1023 molecules= 4 x 1.505 x 1023 atoms

= 6.02 x 1023 atoms

Hope it helps!