Question

calculate the no. of atoms of na in 10.6g of na2co3​

Answer 1

Answer:

1.204×10^23

Explanation:

moles of Na2CO3 = 0.1

1 moles of Na2CO3 contains 2 moles of Na

so 0.1 moles of Na2CO3 will contain 0.2 moles of Na

hence no. of atoms = 0.2 × 6.022 ×10^23

=>1.204 ×10^23