Question

Calculate the no. of atoms present
in 11.5 Litres of Hydrogen(H2) at NT.P. using mainly mole concept​

Answer 1

Explanation: to find no. Of atoms present in 11.5 L 0f H2 gas first we have to find no. of moles

So here in this case we r having gas and we know that...

1mole of gas = 22.4L

So,how many moles in 11.5L

n=11.5/22.4

=0.5moles

Now ...

No.of atoms= n x NA x A

n(no.of moles)

NA(avagadro no.)=6.023 X10^23

A(atomicity)=2 for hydrogen gas(H2)

=0.5 X 6.024x10^23 X 2

Ans. = 6.023 x 10^23