Question

Calculate the no. of atoms present in 180gm of glucose.
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Answer 1

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Calculate the no. of atoms present in 180gm of glucose.

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C6H12O6

12×6+1×12+16×6

=72+12+96

=84+96

=180 atoms

Answer 2

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( C6H12O6 )

12×6+1×12+16×6

= 72+12+96

= 84+96

= 180 atoms

= Ans.

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