Calculate the no. of atoms present in 180gm of glucose.
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There are 24 atoms in one molecule of C6 H12 06. This chemical compound has 6 atoms of carbon, 12 atoms of hydrogen, and 6 atoms of oxygen.
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The no. Of atoms present is 6.022 x 10^23 atoms because 1 mole of glucose is formed in 180gm
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