Question

Calculate the no. of atoms present in 180gm of glucose.
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Answer 1

Answer:

Answer ⤵️

6.022 x 10^23 molecules.

Explanation:

Glucose = C6H12O6

Molar mass = 6(12) + 1(12) + 6(16)

                    = 180 gm

1 mole => 180 gm

1 mole => 6.022 x 10^23 molecules.

No. of molecules present in glucose = 6.022 x 10^23

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Answer 2

Explanation:

molar mass of glucose= 180

mass of given glucose = 180 gm

n=m/M

n=180/180

n=1 mole

n=no. of atoms/ Avogrado's no.

1=N/6.022×10²³

N=6.022×10²³

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