Question

Calculate the no. of atoms present in 24 grams of helium

Answer 1

$\huge\purple{ANSWER:-}$

• 1 mole of He contains 6.023×10^23 atoms.

• 1 mole of He = 4 gm of He.

• So, 20 gm of He contains — (20÷4)×6.023×10^23 atoms = 3.011×10^24 He atoms.