Question

Calculate the no.of atoms present in 46g of NH3

Answer 1

mol. wt. of NH3 = 17gm/mol. given wt of NH3= 46gm.
so, no. of moles = given wt. / mol. wt.
n= 46/17 = 2.6
Now, no. of molecules of NH3= 2.6× NA
Now, no. of atoms = 2.6× NA × 4
= 10 .4 × NA

Answer 2

this is correct answer appreciated bro