Calculate the no.of atoms present in 92 g of Ozone
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Answer:
Explanationno of atoms = mole*Na* atomicity
That is 92/48*6.022*10^23*3:=3.46*10^22
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Answer:
So here we write data first.
Data
Mass of substance given =92g
Atomic mass of substance = 48 amu
NA(Avagedro number) = 6.02×10²³ molecules.
No. of atoms?
By using formula.
No. of atoms = NA ×mass of substance. (given) /Atomic mass or molecular mass or formula mass.
No. of atoms = 6.02×10²³× 92/48
No. of atoms = 11.53×10²³ atoms.
(note:Now you can make your suitable answer by alternating the decimal point.)
Hope it will help you. Thanks!
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