Question

Calculate the no. Of c h and o atoms in 72.5 grams of iso propanol

Answer 1

Answer:

Explanation:

C3H7OH - Molecular mass = 60

72.5 g is 72.5/60 = 1.208 moles

1 mole of C3H7OH contains 3N atoms ( N= 6.023 x 10^23) of C

1.208 moles contains 1.208 x 3N atoms

= 3.624N atoms of C

= 2.183 x 10^24 atoms of C

Similarly

no.of O atoms = 1.208N atoms = 7.276 x 10^23 atoms of O

Answer 2

Explanation:

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