Question

calculate the no. of chromium atoms in 1.47 grams of potassium dichromate.​

Answer 1

Answer:

6.02*10^21

Explanation:

molar mass of K2Cr2O7 is 294

Hence no. of moles will be 1.47/294 = 0.005

each mole has 2*6.022*10^23 Cr atoms = 1.204*10^24 Cr atoms

Hence in 0.005 moles there will be

0.005*1.204*10^24 =6.02*10^21 Cr atoms